提交时间:2026-05-06 18:43:52
运行 ID: 439163
#include <iostream> using namespace std; int main(){ int x,y; cin>>x>>y; if(y>=x){ cout<<1; return 0; } int t=((x-y)/(y-1))*2+1; if((x-y)%(y-1)!=0){ t+=2; } cout<<t; return 0; }