提交时间:2026-04-15 20:03:03
运行 ID: 436466
#include <iostream> #include <algorithm> using namespace std; int main() { int M, N; cin >> M >> N; int def[1005], atk[1005]; // 读 M 个防御:每个防御单独一行!!! for (int i = 0; i < M; i++) { cin >> def[i]; } // 读 N 个攻击:每个攻击单独一行!!! for (int i = 0; i < N; i++) { cin >> atk[i]; } // 从小到大排序 sort(def, def + M); sort(atk, atk + N); int i = 0, j = 0; while (i < M && j < N) { if (atk[j] > def[i]) { i++; j++; } else { j++; } } int sum = 0; if (i == M) { // 必须全部破防 for (int k = j; k < N; k++) { sum += atk[k]; } } cout << sum << endl; return 0; }