//A. 【C2-4】求恰好使s=1+1/2+1/3+…+1/n的值大于X时n的值 #include<bits/stdc++.h> using namespace std; int main(){ double s=0; int x; cin>>x; double n=0; while(s<=x){ n++; s=s+1/n; } cout<<n; return 0; }