提交时间:2025-05-18 12:30:46

运行 ID: 323503

#include <iostream> #include <cstdio> using namespace std; int main(){ int n, a, b; cin >> n >> a >> b; int sum = 0; for (int i = 1; i <= n; i++){ int x = (i - 1) % a + 1; int y = (i - 1) % b + 1; if (x == y) sum++; } cout << sum << endl; return 0; }