| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 443806 | 任虞昊 | [在线测评解答教程] 求和 | C++ | Accepted | 100 | 1 MS | 184 KB | 126 | 2026-06-06 22:07:00 |
#include<stdio.h> int main() { int n; while (scanf("%d", &n) != EOF) { printf("%d\n", n * (n + 1) / 2 ); } return 0; }