Online Judge
| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 368926 | 许安哲 | [在线测评解答教程] 求和 | C++ | Accepted | 100 | 5 MS | 184 KB | 126 | 2025-12-18 16:45:02 |
Tests(10/10):
#include<stdio.h> int main() { int n; while (scanf("%d", &n) != EOF) { printf("%d\n", n * (n + 1) / 2 ); } return 0; }