Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
---|---|---|---|---|---|---|---|---|---|
356012 | 任晨熙 | [在线测评解答教程] 求和 | C++ | Accepted | 100 | 3 MS | 192 KB | 126 | 2025-10-12 18:33:39 |
#include<stdio.h> int main() { int n; while (scanf("%d", &n) != EOF) { printf("%d\n", n * (n + 1) / 2 ); } return 0; }