| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 338556 | 陈信宇 | [在线测评解答教程] 求和 | C++ | Accepted | 100 | 4 MS | 192 KB | 126 | 2025-08-07 16:52:36 |
#include<stdio.h> int main() { int n; while (scanf("%d", &n) != EOF) { printf("%d\n", n * (n + 1) / 2 ); } return 0; }