| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 326697 | 顾子丞 | 【C2-6】循环查找最大值 | C++ | Accepted | 100 | 1 MS | 248 KB | 210 | 2025-06-14 14:28:24 |
#include<iostream> #include<iomanip> using namespace std; int main(){ double n,a,s=0,ma=0; cin>>n; for(long long i=1;i<=n;i++){ cin>>a; if(ma<a){ ma=a; } } cout<<ma; return 0; }