Online Judge
| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 313155 | 朱宸宇 | 【C2-2】 编程求1+1/2+1/3+...+1/n | C++ | Wrong Answer | 40 | 1 MS | 252 KB | 215 | 2025-03-19 17:34:15 |
Tests(2/5):
#include <iostream> #include <cstdio> using namespace std; int main() { double n; cin>>n; double sum=0; for (double i=1; i<=n; i++) sum+=i/(n*1.0); printf("%.3lf",sum); return 0; }